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If a projectile travels distance R at 38.6 degrees above horizontal, what angle in degrees above...

If a projectile travels distance R at 38.6 degrees above horizontal, what angle in degrees above horizontal would give the same range?

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Answer #1

Concept: we use the formula for range for a projectile motion and use the fact that sinθ = sin(π-θ)

amge of a projechle is glwm by Vospe of launch e angle of Launeh R 22 assuming v. be savnefor ooth So m@ Cunos sn@-פ 2.0.- ig0°-242 becaure, d 2(38-6)130 - 202***************************************************************************************************
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