Question

Question 9.

Part b.

According to Henry's law:

volume of O2/1000 mL H2O = (85/760) atm * 0.024 mL O2/mL H2O

i.e. The volume of oxygen = 2.684 mL

Part c.

According to Henry's law:

volume of CO2/1000 mL H2O = (38/760) atm * 0.88 mL CO2/mL H2O

i.e. The volume of carbon dioxide = 44 mL

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