Question

(a) In a gaseous sample of oxygen atoms and diatomic oxygen in equilibrium at 298K and under a pressure of latm, what fraction of it is dissociated? (b) At what temperature is the sample 1% dissociated? (c) At 298K and under a pressure of 10,000 atm, what fraction is dissociated?

Answer 1

classmate Date Page Entropy of 0 2161.0 59 t/mol-k. Enthalpy of o = 249.18 kJ/mol. Entropy of O₂ = 205.15 t/mol-k 0220 <H= 2(0) - SH (O2) = 2x249.18 -0 8 498 36 kJ/mol. 45 > 2 x 45 (0) - 45(02) __ z 2X 161.059 205.15 let a ? 116.968 Trol-) : At 298k, - - 1 x6 = 4H-TAS 2 498:36 - 298 X 116.968810? - 463.50 kJ/mol. Now, Ga-RTlink - * 463 50 a ax 103 = -298x8.314 ink ☆ ihka - $63.50x103 29888:314 2-187.08. 12 - 187085.65 032 Trust - 2007 k2 [02] 5.658 10 82 2007 [2 ] L2101 25.65 x 10 32 IT02 at 298k 5.65 X 100 % dissociation oceion. Scanned with CamScanner

classmate Date Page now for 1% dissociation. 2 [ o1 201 [0 ] aq " ka= 2 = 0.0202 Now A6=-RT luk | = 463 50 X 10° = - 8 3 14 x 1 x 1 (0 0202) => T = 14 287.47 k Thus at 14287.47K 1% dissociation occurs. Now, AG=RT luk [PV=nRT => 463.50 xh - PV link RT = PV I for n= 1, V=22-4 like #463-5001 Liv=22.4x103 m3 Now I atm = 1013 25 pa 462.50% 60% - 10000 X 10/325 x 22-48703 =-0.0204 ² lnk= -463 => kz 0.9798 10 X 10/325 X 22-4 X10-3 Now, k =- 102 2207 10₂7 0.9798 2[0]= 0.9798> [02 7.[ 027 + % of alor = 100 g to 9098 tot 7 [027 to 97987027=100 => [027=50.5 frs Scanned with dissovahom = 100 - 50.5 = 49.49. CamScanner .