Question

The following questions involve the following equilibrium system:                                       

                                                Cd(OH)₂ (s) ----> Cd²⁺ (aq) + 2OH^- (aq)

1. Write the solubility product constant expression for a saturated solution of Cd(OH)₂.
2. Determine the molar solubility of Cd(OH)₂. The K_sp value for Cd(OH)₂ is 1.2 x 10^-14.
3. If a 100.0 mL sample of the saturated solution of Cd(OH)₂ is titrated with 0.00100 M HCl, how many mL of HCl would be required to neutralize this solution? Write the molecular, complete ionic, and net ionic equations for the reaction that occurs.
4. Is the concentration of OH^- found from the titration the same as the equilibrium concentration of OH^- in the saturated solution of Cd(OH)₂? Explain your answer.

Answer 1

calon w - Cd2+ + 200 an let x o to Cd Con . according be salubility of above equation. [ed 2+] = x Con-] = 220 a ksp = [carta [ona 2 .. . [3] [226? a yace? kop : 1.2 x 10-14 12x 10 15 4 x ² = 12 X 10-15 x² = 3x10-15 x = 353 x 10-5 a 1.44 X10-5 Malar Salubility of Calon) 1.44X10-s Con = 2x 2.88 X10-5 m. 400 ml a Valume = o.gl males as [on] = 2.88 x 10-5 X ool . 2.88 x 10-6 males of saln Luty required of calon = to neutralize 2.88 X 10 6 mal saturated

Valume of nu = No. of males Malarity 2.88 X10-6 0.001 = is 2.88 X 10 L 2.88 3 mL @ No, conch of on same of Cl equilibrium saturated solution of found from concentration carour. titration is of our in As we form no in salution is mare on: on adding in e sain add a na, it ow more and of concr than the react with on to done will dissaare of on from titration equilibrium conch as will dissale titrant, more and cond Calong increases