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daton number for each coment in the sono 7 pts) What is the 8. (T ) darily the w ing and reducing agents in the following equ
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Answer #1

C2O7 2-
Sum of oxidation numbers = -2
let x be O.N for Cr,
for Oxygen, O.N = -2

then 2x +7[-2] =+2
2x= -2+14 = +12
x= +6
O.N for Cr = +6
*********************
6HI + 2HNO3 ---> 3I2 + 2NO + 4H2O

oxidizing agent will undergo reduction

Reducing agent will undergo oxidation

In HI , O.N [oxidation number] for I is -1 ,while in product I has O.N= 0
Thus HI undergoes oxidation . Hence HI is reducing agent****

And HNO3 , nitrogen in +5 oxidation state.In NO ,the nitrogen in +2 oxidation state,Thus HNO3

undergone reuction .So oxidizing agent is HNO3***
*********
9)
balanced reaction given below
2 HCLO4(aq) +Li2CO3(s) = CO2(g) + H20(l) + 2LiClO4(aq)
*************
NH3 ionize partially in water
Hence it is

weak electrolyte and weak base
****************

11) NaOH, CaBr2, MgCO3, Na2SO4 all are ionic hence strong electrolyte

KC2H3O2 is not a strong electrolyte
**************************

12)
According to solubility rules all nitrates are soluble

So Soluble salt is

Co(NO3)2
*************
ALL solved


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