91 169 305 330 335 389 393 394 402 410 420 449 452 455 459 465...
Homework Answers
Difference = 537-91= 446
if you want 10 class differences then the width of the class interval = 446/10= 44.6 next integer = 45
which is not the class limit
The lower class limit will be 91 and the upper class will be 91+45 = 136.( 91 -- 136) first class interval and its class limit
So, 44.6 is not a correct class limit.
91 169 305 330 335 389 393 394 402 410 420 449 452 455 459 465...
91 169 305 330 335 389 393 394 402 410 420 449 452 455 459 465 468 471 472 474 475 479 481 486 487 505 508 509 511 512 517 519 530 537 1. Construct a frequency distribution table using 10 classes. Start the lower limit with 91. 2. Using Chebyshev’s Theorem, find the range of data for which 75% of the data falls.
91 169 305 330 335 389 393 394 402 410 420 449 452 455 459 465...
91 169 305 330 335 389 393 394 402 410 420 449 452 455 459 465 468 471 472 474 475 479 481 486 487 505 508 509 511 512 517 519 530 537 For the class limit is 44.6 correct to use? 3. Construct a frequency distribution table using 10 classes. Start the lower limit with 91. 4. Construct a histogram for the data set and describe the shape and distribution of the data. 5. Using Chebyshev’s Theorem, find...
91 169 305 330 335 389 393 394 402 410 420 449 452 455 459 465...
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