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A 2.56-kHz tone is being produced by a speaker with a diameter of 0.211 m. The...

A 2.56-kHz tone is being produced by a speaker with a diameter of 0.211 m. The air temperature changes from 0 to 21 oC. Assuming air to be an ideal gas, find the change in the diffraction angle θ.

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at 0c 9peed of sound Is 33[ms mou %, different ter?yuturC at 2 273 331 +273 V= 343.44 n/s 331 2.56 x 1 03-01292、 0. 21 冫上= 343.44 งั้ diffraehn ande O.211 mouw chamce in dis^oacfia aryle 48 2.4qy

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