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If 14.4 moles of Cu and 17.4 moles of HNO3 are allowed to react, what is...

If 14.4 moles of Cu and 17.4 moles of HNO3 are allowed to react, what is the maximum number of moles of NO that can be produced?

3 Cu + 8 HNO3 → 3Cu(NO3)2 + 2NO + 4H2O

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Answer #1

The given reaction is - 3 eut 8 HNO 3 73 Cu(NO3)2 +2 No+4H30 Here, 3 mols eu react with 8 mols HNO 3 produas 2 mols No. Here,

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