Question

5 5.6. The following is a reaction with its initial conditions (amounts of each substance): 6H2 + P - 4PH; nodis 10.0 mol 3.0 mol 3.5 mol olg (a) Determine & if 1.5 mol of P4 reacts to make products. (b)ls it possible for & to equal 3 in this case? Why or why not? t

Answer 1

6 H₂ + PA 4 PH₂ mole P rearts with 6 105 mole PA will react with mole H₂ 6x 105 = : 9 mole H₂. and give product PHz = (4x 105) mole = 6 mole PHz. final concentration So inital H 10 concentration mol (10-a)= mol 3 mol (3-105) = 105 mol mol PH₂ 3.5 mol (3.5+6) = 905 mol. final mol of PH₂ - initial mol of PH₂, stoichiometric coefficient of PH₂

9.5-3.5 15 deter- For this type of mine which reactant question ist we have to is the limiting reagent. mole Pq reacts with 6 mole H₂ . 3 3. Pq will react with (683) = 18 mole Hz. Hence, here limiting reagent of H₂ (10 moll is less than is Hy as it actually given amount required. of Now, we have product can be to calculate the amount formed (maximum). 6 mole . 10 mole H₂ gives a mole PH2 He will give (1 x 10) mol PHz = 6.67 mol PHz. 49 initial PH₂ maximum amount of PHz can be formed = 6.67 mole. 3.5 mol " Final PH2 = 13.5+ 6.67) = 10 17 mol i maximum = 10.17 - 3.5 4 = 1.67
Hence for this reaction extent of reaction can not be 3. Maximum value it can attain is 1.67 .