Dear student,
we have PH of the solution which gives us H+ concentration from there we are going to get Ka from the initial concentaraion and assuming a change of x for the reaction, the question is solved below.If something is not clear or need further clarification please feel free to comment here without hesitation.
![mono protic acid (x ) let be the acid] which gives one proton (ht) HX - * * коъ Сңіх Hx] oo Initial 0.014 change as ts to ol4](http://img.homeworklib.com/questions/d8d984f0-6f66-11ea-b0ad-931803223eea.png?x-oss-process=image/resize,w_560)

Enough of a monoprotic weak acid is dissolved in water to produce a 0.0140 M solution....
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0106 M solution. The pH of the resulting solution is 2.69. Calculate the Ka for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0165 M solution. The pH of the resulting solution is 2.34 . Calculate the Ka for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0113 M solution. The pH of the resulting solution is 2.64 . Calculate the Ka for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0160 M solution. The pH of the resulting solution is 2.41 . Calculate the Ka for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0183 M solution. The pH of the resulting solution is 2.47. Calculate the pKa for the acid.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0180 M solution. The pH of the resulting solution is 2.63. Calculate the K, for the acid. K =
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0182 M solution. The pH of the resulting solution is 2.40, Calculate the K, for the acid. K.=
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0181 M solution. The pH of the resulting solution is 2.41. Calculate the K, for the acid. KE 9.58 x10--
a. Enough of a monoprotic acid is dissolved in water to produce
a 0.0163 M solution. The pH of the resulting solution is 2.51.
Calculate the Ka for the acid. Ka= ________
It's not 5.86 10-4. I tried it and it
wasn't correct.
b. The Ka of a monoprotic weak
acid is 6.61 × 10-3. What is the percent ionization of a 0.108 M
solution of this acid? Percent ionization= ___________
it's not 24.72 %. I tried it's also incorrect.
Enough of a monoprotic acid is dissolved in water to produce a 0.0192 M solution. The pH of the resulting solution is 2.53. Calculate the Ka for the acid.