Question

Enough of a monoprotic weak acid is dissolved in water to produce a 0.0182 M solution. The pH of the resulting solution is 2.40, Calculate the K, for the acid. K.=

Answer 1

Sol: Curen H-A - 6.0 182m PH 2.40 Find; kasu? pH- – dag City= 2.40 Now = {4} = 102.40 -0.0039810 et HA - At Lwitical 0.0172m à 0 Edu 0.0039816 0.0182-0.0039 slog 0.003 as 10 82-0.003s on =) ka? (0.003a8s 1.5-8486x 10 0.01922 0.01422 16 x 10 - WrX 1oYx10? ka = 1.12 x 157 19?  

Sol: Given & Cueak acid [h = 0.0182m pH = 2.40 - pH-– dag (t} = 2.40 - C+3 = 22.40 = 0.0039812 2 [A]at even Now) t t HA Car - [] Slad) Initial o.o182 m. 0.0039812 at 0.0152-0.0039812 0.003981 -0.0142189 (0.00398121² ker [At] (4] Rap - 0.0142188 50.00 11147 X18 5 kar 1. 1147410