Question

What volume of 0.829 M KOH solution is required to make 3.54 L of a solution with pH of 12.5? Express your answer with the appropriate units. TH HÀ • • • Ea ? V = 0.13 L Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Review your calculations; you may have made a rounding error or used the wrong number of significant figures.

Answer 1

Volume needed = 0.135L or 135 ml

Explanation:

pOH + pH = 14

pH = -log[H⁺]

And pOH = -log [ OH^{​​​​​-}]

No. of moles = Molarity × volume

I.e n = CV

pH = 12.5 pOH = 14-ph pon = 14- 12.5 = 105 And low por = -log[104] [on-] = 10 -POH [OH-] = 10-15 = 316 X10 - 2M Molarity of stock solution = 0.8299 volume needed - V Molarity of required solution - 30/6x10 - 2M Volurce of required solution = 3.542 using cr = Cara (vo. of roles and voca = (No. of Heales) required soen Because 0.8294 xV - 3016810-2 M X 3.54L 3.16X10-2 M X 3.54L = = /3.5x70 16 0.899 volume needed = 135 ml /