Question

Date of Lab Numbers 1-4: Apply rule (a) or (b). Show every step of your work, including units. I. 41.57s + 0.016s 2. (1.57m)(12.02m)- 3. 1502 kg-3.14 kg Apply rules (a) and (b) at every step, showing work. Remember, order of operations requires division before addition. Do not find common denominators with this problem. 4. 999.0m+888m 444m- 6.00s 5.00s 4.80s work #4 again, by the simplified procedure (Rule C) for calculations with measured data. Show only this much work: The original problem, the calculator result, and your final (rounded) answer. 6. Find the percent difference between 0.058 g and 0.043 g, with respect to the 0.043 g value.

Answer 1

Ans.

1)

41.57s + 0.016s = 41.586s, since the number of the significant digits is 2 in 0.016 s, so we round the answer to two significant figures. The 3rd digits in the sum is greater than 5, we round up the sum.

The sum = 42. s

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2)

1.57 m x 12.02 m = 18.8714 m² . SInce the number of the significant figures in 1.57 m is three we round the answer to three significant figures. The 4th digit in the product is greater than 5 so we round up the answer.

The product = 18.9 m²

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3)

1502 kg - 3.14 kg = 1498.86 kg, The number of the significant figures in 3.14kg is three we round the answer to three significant figures. Writing the answer in scientific form: 1.49886*10³ kg.

The 4th digit in the product is greater than 5 so we round the answer up.

The difference = 1.50x10³ kg

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4)

Performing each division before adding them.

i) 999.0m/6.00s = 166.5 m/s and this rounds to 166 m/s (6.00s has 3 sig fig and the digit before 5 is even so we ignore 5)

ii) 888m/5.00s = 177.6 m/s and this rounds to 178 m/s

iii) 444m/4.80s = 92.5 m/s

Now we add them up

The answer = 166 + 178 + 92.5 = 436.5 m/s and this rounds to 436 m/s(answer)