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8) Dissolving 7.75 g of a substance into 825 g of benzene at 298 K raises...
A solution is made by dissolving 0.592 mol of nonelectrolyte solute in 767 g of benzene. Calculate the freezing point, Te, and boiling point, Tb, of the solution. Constants can be found in the table of colligative constants. T = Colligative Constants Constants for freezing-point depression and boiling-point elevation calculations at 1 atm: Solvent Formula Kf value* Normal freezing Kb value Normal boiling (°C/m) point (°C) (°C/m) point (°C) water H20 1.86 0.00 0.512 100.00 benzene 5.12 5.49 2.53 80.1...
Pure benzene, C6H6, has a molar mass of 78.114 g mol-1, a density of 0.8765 g mL-1, a freezing point of 5.45°C, and a boiling point of 80.2°C. Its freezing point depression and boiling point elevation constants are: Kf = 5.07°C m-1; Kb = 2.53oC m-1. A solution was made by taking 33.88 g of an unknown nonelectrolyte and dissolving it in 175.0 g of benzene. The measured freezing point of the solution was 1.65oC. Calculate the molar mass of...
A solution is made by dissolving 0.749 mol of nonelectrolyte solute in 861 g of benzene. Calculate the freezing point, Tf, and boiling point, Tb, of the solution. Constants may be found here. Solvent Formula Kf value* (°C/m) Normal freezing point (°C) Kb value (°C/m) Normal boiling point (°C) water H2O 1.86 0.00 0.512 100.00 benzene C6H6 5.12 5.49 2.53 80.1 cyclohexane C6H12 20.8 6.59 2.92 80.7 ethanol C2H6O 1.99 –117.3 1.22 78.4 carbon tetrachloride CCl4 29.8 –22.9 5.03 76.8...
A solution is made by dissolving 0.745 mol of nonelectrolyte solute in 853 g of benzene. Calculate the freezing point and boiling point of the solution. The normal freezing point of benzene is 5.49 °C and the normal boiling point of benzene is 80.1 °C. Assuming 100% dissociation, calculate the freezing point and boiling point of 0.570 mol of AgNO3 in 1.00 kg of water.
A solution is made by dissolving 0.585 mol of nonelectrolyte solute in 877 g of benzene. Calculate the freezing point, Tf, and boiling point, Tb, of the solution. Constants can be found in the table of colligative constants. Constants for freezing-point depression and boiling-point elevation calculations at 1 atm: Solvent Formula Kf value* (°C/m) Normal freezing point (°C) Kb value (°C/m) Normal boiling point (°C) water H2O 1.86 0.00 0.512 100.00 benzene C6H6 5.12 5.49 2.53 80.1 cyclohexane C6H12 20.8...
2. A solution of an unknown molecular substance is prepared by dissolving 0.50 g of the unknown in 8.0 g of benzene. The solution freezes at 3.9°C. Determine the molar mass of the unknown. (Benzene has a freezing point of 5.5°C and a Kfvalue of 5.12°C/m) 10
A substance used to make detergents. A solution of 5.00 g of that substance in 100. g of benzene freezes at 4.100°C. What is the molar mass of this substance? (freezing point of benzene is 5.444°C, molal freezing point depression constant of benzene is 5.12 oC/m) (Consider the # of significant figures.)
The molar mass of unknown molecular compound is determined using freezing point depression. The substance is dissolved in benzene (C6H), an organic solvent. Use the data below to determine the molar mass of the substance. 8.65 g Mass of unknown compound Freezing point of solution Volume of benzene -10.21°C 35.0 mL 5.53°C Freezing point of benzene Density of benzene Kf for benzene 0.8765 g/mL 5.12°C/m Molar mass = g/mol
A solution is made by dissolving 0.539 mol of nonelectrolyte solute in 775 g of benzene. Calculate the freezing point, Tf, and boiling point, Tb, of the solution.
1.A solution that contains 15.581 grams of benzene (molar mass = 78.1 g/mol) in 420 g of cyclohexane freezes at a temperature 9.50 ºC below the freezing point of pure cyclohexane. Calculate the molar freezing point depression constant, Kf, for cyclohexane. 2. The molar boiling point elevation constant for water is 0.512 ºC/m. What is the boiling point of a solution containing 673 g of water and 78.0 g of CaCl2? 3. A solution containing 32.0 g of an unknown...