Question

I know its quite a bit but I would really appreciate the help. Thank you!

The compound zinc(II) chloride is incorrectly named. Rename the compound correctly. correct compound name: zinc (II) dichloride

Answer 1

Coulombs formula for the electrostatic force of repulsion between two similar electric charges is as follows: F=K9403 Here, F→ magnitude of force of repulsion K→ Coulombs constant =9.0x10Nm/c? 91 and 42 → charge of protons d distance between protons --------------- ------ -- ---- Charge of Nat, 9 = +1.602x10-19 C Charge of I", 9,= -1.602x10-19 C Distance between protons, d= (102+220) pm =322 pm = 322x10- m = 3.22x10-10 m Coulombs constant, K =9.0x10° Nm/c According to Coulombs law, magnitude of force of repulsion is, F = None = (9.0x10°Nm/62 (+1.602x10-°C)(-1.602x 10-20 C) (3.22x10-10 m) =-223x10- N Energy = (3.22x10-m)(-2.23x10°N) = -7.18x10-19 Nmx- iN-m = -7.18x10-19 x 1 kJ 6.022x1023 10 J 1mol = -7.18x10-22 kJ x 6.022x10° 1 mol = -432 kJ/mol

---------------------------------------- Charge of Ca²+, 91 = 2(+1.602x10-5C) Charge of $2,92=2 -1.602x10-C) IOnic radius of Ca2+ = 100 ppm IOnic radius of S- = 184 ppm Distance between ions, d = (100+184) pm = 284 pm = 284x10-12 m = 2.84x100 m Coulombs constant, K =9.0x10' Nm/c? According to Coulombs law, magnitude of force of repulsion is, F = 9 = (9.0x10°NmⓇlc2) 2(+1.602x10-1°c)2(-1.602x10-10) (2.84x10-10 m) = -1.14x10 % N 1J Energy, AE= (2.84x10–m)(-1.14x10* N) = -3.24x10-18 N-mx- = -3.24x108 5x hype = -3.24x10-21 kJ iNm