Question

A) As B) Sb C) P D)Bi E)N 10. In which of the series of elements listed below would the elements have most nearly the same atomic radius? A) Na, K. Rb, Cs B)F, CI, Br.I C) Na, Mg. Al, Si D) Sc, Ti, V, Cr E)B, Si, As, Te Which of the following properties, in general, increases from left to right across a period in the periodic table? A) ionic charge 11、 B) atomic radius C) density D) ionization energy E) metallic character The change in energy for which of the following processes represents the first of bromine? 12. onization energy D) Br(g) → Br.(g) + e- E) Br.(g) → Br.(g) + 2e. The change in energy for which of the following processes corresponds to the second ionization energy of barium? 13. 14. An atom of which of the following elements has the smallest first ionization energy? An atom of which of the following elements has the largest first ionization energy? A)N B) Sb C) As D)P E) Bi 15. According to the general trend in electron affinities, which group (or family) of elements tend to form the most stable anions in the gas phase? A) noble gases B) halogens C) transition metals metals 16. D) alkaline earth metals E) alkali The element selenium is in the same group as sulfur. Which of the following is the formula of selenous acid? 17. When the cations Na', K', Rb', Cs' are combined with chloride ion in the gas phase to form ion pairs, which pair formation releases the greatest amount of energy? A) KCI B) All release the same amount of energy. C) RbCI D) NaCI E) CsCI 18. 19. In the Borm-Haber cycle for KF(o), which of the following processes corresponds to the electror affinity of F?

Answer 1

Answers- 9. The valance shell electronic configuration of As, Sb, P, Bi and N are [Ar]3d45-4p. [Kr]4d5s 5p, (Ne]3s 3p, [Xe]4 85d6s6p' and (He]2s²2p' respectively. The atomic radius decreases as me move from left to right in a periodic table due to increase in effective nuclear charge and increases as me move down in a group of a periodic table due to increase in number of shells. Hence, Bi is having largest atomic radius. 10. The transition metal series, that is, option d is having similar atomic radius this is due to the presence of inner d orbital electrons. Due to the poor screening effect of d-orbital, they are not able to shield the outer electrons from the core nucleus. All other options have elements of same groups or diagonal group, where atomic radius increases down the group. Hence, the correct option is d.