a)
let g is the acceleration due to gravity
the time taken to move up T/2 and the time taken to fall back is T/2
while fallling down,
H = voy*t + (1/2)*g*(T/2)^2
H = 0 + (1/8)*g*T^2
g = 8*H/T^2 <<<<<<---------------Answer
b)
we know, g = G*Ms/R^2
so,
G*Ms/R^2 = 8*H/T^2
Ms = 8*H*R^2/(G*T^2) <<<<<---------------Answer
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