Question

can someone please help me do this

Th ese are based on percent by Nam Formula Mw Pressure Volume Moles G ram Density 45 Chlorine 40 Xenon 100%. Mixture Igr.15 1.206 7.5 Govering tations: 1.20 299 Pressure (atm) - Temperature ( Volume = Gas Constant OOR The values given are based on percent by Name 15% Oygen Oxygen 455 Chlorine chlorine 40% Xenon Xenon 100% Moxture Mixture Governing Equations Pressure atm) Temperature Volume (L) - Gas Constant R 0082

Answer 1

soll- 15. oxygen t 40 7. Xenon & 45 %. Chlorine given percent are by volume loome mixture so 15ml Yo mi 45 mi oxygen im xenon in chlorine im loome mixture loomi mixture oxygen (0₂) Chlorine (9₂) xenon (xe) 16 70.9 131.3 Total volume is 1.5L so volume of O2 is 15x7.5= 1.125L loo Volume of ch is 45x7.5= 3.3756 Volume of txe is 40x7.5 = 3.0L density of at STP ₂ is a is te is 1.429 g/L 3.2g k 311 g/L