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3. A mixture of Cu20 and CuO of mass 8.828 g is reduced to copper metal w Cu:0 + H2 → 2Cu + HO CuO + H2 → Cu + H2O If the mas
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Suppose the mass of CuO = x gram Therefore the mass of 20 = (8.828-x) gram. moles of CuO =_ moles moles of CuO = 8.828-2 mole0.1136 X 143x79.5 = 1403,652 - 159 x + 143X 1291.4616 = 1403.652 - 16% 16x = 1403.652-1291-4616 16x= 112.1904 X = 112.1904 [x

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