E(S(1))=puS(0)+(1-p)dS(0)
S(0)=E(S(1))/exp(r)
(S(1))=E(S(2))/exp(r)
S(0)=E(S(2))/exp(2r) similarly,
S(0)=E(S(n))/exp(nr)
Now if S(n)=S(0) then
S(0)=S(0)/exp(nr)
exp(r)=pu+(1-p)d
exp(nr)=1
nr=0 then only possible condition is r=0
For all values of n>=1 we would have this case of S(n)=S(0)
p=1-d/(u-d)
u>1>d
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