18. Given the following equilibrium constants, K. (HSO4) = 1.2 x 102 K(CHCO2) = 5.6 x...

Question

Question

science chemistry

Answer 1

Answer #1

Solution:

Option D

Calculation:

For the given reaction, the equilibrium constant (K) is written as,

K = [SO4^2-] [CH3COOH] / [CH3COO-] [HSO4-]

The expresdion for Ka of HSO4-:

Ka = [SO4^2-] [H+] / [HSO4-] ----(1)

The expression for Kb for CH3COO-:

Kb = [CH3COOH] [OH-] / [CH3COO-] ---(2)

The expression for Kw of H2O:

Kw = [H+] [OH-] ----------(3)

Multiply equation 1 by 2 and dividing by equation 3,we get

Ka x Kb /Kw = K

Thus,

K = Ka x Kb /Kw

K = 1.2 x 10^-2 x 5.6 x 10^-10 / 1 x 10^-14

K = 6.7 x 10^2

Answer 2

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