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For 300.0 mL of a buffer solution that is 0.325 M in CH3CH2NH2 and 0.300 M...

For 300.0 mL of a buffer solution that is 0.325 M in CH3CH2NH2 and 0.300 M in CH3CH2NH3Cl, calculate the initial pH and the final pH after adding 0.005 mol of NaOH.

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Answer #1

CH₂ CH NH: kg = 6.3x104 pkb_ - 10g Kb = -10g (6-3x104) = 3.2 pott a pkb tog [cts CH, Wher] [CH, CH Nit] polt_ 3.24109 0 3 = 3

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