Question

The following synthesis is done in 3 steps.
1. The selective oxidation of alcohols.
2. Aromatic Grignard
3. Carbon-Carbon coupling.

Perform stoichiometric calculations to obtain 1 ml of the final product, using the concept of limit reagent in the synthesis of geranial and phenylmagnesium bromide. assuming 100% yield.

сH MgBr CH3 CH3 ОН Hас CH3 Нас ??? Phenylmagnesium bromide Geranial

The complete equations of the synthesis of geranial and grignard reagent are shown below. (They are needed to calculate the final 1 ml of product of the reaction above)

Density of Final Product: 0.962 g/cm³

Molecular weight of Final Product: 230.35

Please upload all the calculations required and according to stoichometry define the limit reagent in all the reactions (3).

Answer 1

Density of Final Product = 0.962 g/Cm3

Volume required to be prepared = 1 mL

mass = Density x volume

Mass = 0.962 x 1 = 0.962 g

No, of moles = weight in gram/molecular weight

No of moles = 0.962/230.35 = 0.00417 moles

Assuming 100 % Yield we need to generate 4.17 millimoles.

To generate 4.17 millimoles of final product, we need 4.17 mmoles of Geraniol and Phenyl magnesium bromide each

Molecular weight of Geranial =152.24

Weight required (Geranial) = no. of millimoles x molecular weight = 4.17 x 152.24 = 624.18 mg = 0.624 g

Weight Required (Phenyl magnesium Bromide) = 4.17 x 181.31 = 756.06 mg = 0.756 g