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5. In a titration similar to the one you will perform today, it is found that 24.66 mL of 0.1012 M NaOH is required to titrat
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Answer #1

2 Na OH & R-COOH), QR-COONa + 2 0 moles of NaOH = Molarity & volume 20. 1012m x 24.66 m2 = 2.495 mmol 2 motes of na oH neutra

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