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4. 1.013 g of an unknown solid mixture contains some ascorbic acid. It is dissolved in 25.0 mL of DI water, and after additio

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Answer #1

weight of the unknown sample = 1.013 g

sample was dissolved in 25.0 ml water and taken for analysis

it take 17.7 ml of 0.00480 M iodine

moles of iodine required = 8.5*10^-5 M

so the sample contains 8.5*10^-5 M of ascorbic acid

weight of ascorbic acid = 176.12*8.5*10^-5 = 0.015 g

percent of ascorbic acid = 1.48%

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