Ascorbic acid (vitamin C, MM 176.124 g/mol)) can be determined using an iodometric back titration. A...
2. A 0.1000 g sample of KBrO3 was dissolved in dilute acid and treated with an excess of KI. BrO3 +91 +6H+ → Brº+ 313 + 3H20 The generated 13. required 11.92 mL of a Na2S2O3 solution to reduce it to 1. Use the above balanced equation and those found in the introduction to determine the molarity of the Na2S2O3 solution. 3. The following data was obtained for an iodometric titration of an ascorbic acid tablet. Mass of tablet: 1.2191...
Calculate the weight percent of ascorbic acid in a tablet of Vitamin C from the following data: A 100 mg sample of a crushed Vitamin C tablet was dissolved in 40 mL of H2SO4 and 20 mL of water. Two grams of KI and 35 mL of 0.0107 M KIO3 solution was added, and the mixture titrated to a starch endpoint. The titration required 12 mL of 0.0790 M thiosulfate solution.
I understand part a, I need help with B and C. Thanks!
6-B. Vitamin C (ascorbic acid) from foods can be measured by titration with 13: CH4O6 + + H2O = C,H,O + 30 + 2H Ascorbic acid Triiodide Dehydroascorbic acid FM 176.126 Starch is used as an indicator in the reaction. The end point is marked by the appearance of a deep blue starch-iodine complex when unreacted 15 is present. (a) If 29.41 mL of Iz solution are required...
16 7-2 Titration Calculations Ascorbic acid (vitamin C) reacts with according to the equation Starch is used as an indicator in the reaction. The end point is marked by the appearance of a deep blue starch-iodine complex when the first fraction of a drop of unreacted remains in the solution. TI (a) Stundurdization: If 29.41 mL of iodine solution is required to react with 0.197 0 g of pure ascorbic acid, what is the molarity of the iodine solution?! (b)...
A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NAOH solution. From the results of this titration, the mg of ascorbic acid in the tablet was calculated. Molecular formula of ascorbic acid: C6H806 Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 14.47 Concentration of NaOH in mol/L, 0.1964 Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg). Answer:
Vitamin C (ascorbic acid) from foods can be measured by titration with I3-If 29.41 mL of I3- solution are required to react with 0.1970 g of pure ascorbic acid, what is the molarity of the I3- solution? A vitamin C tablet containing ascorbic acid plus inert binder was ground to a powder, and 0.4242 g was titrated by 31.63 mL of I3-. How many moles of ascorbic acid are present in the 0.4242 g sample? Find the weight percent of...
You run a titration experiment to determine the mass of ascorbic acid (MM=176.12 g/mole) in a vitamin C tablet. The tablet was dissolved in 100mL of water and the titration required 23.0 mL of 0.5M NaOH for complete neutralization of the acid, according to the following reaction: AscH2 (aq) + 2NaOH (aq) -> Asc^2- (aq) + 2H2O (l) + 2Na^+ (aq) a) Calculate the moles of NaOH used. b) Calculate the moles of acid in the solution. c) Calculate the...
Vitamin C in a titration with potassium iodate
References Mailings Review View AaBbcode Abccdee AaBbcc No Spacing Heading 1 Normal 3. A suitable method for the determination of vitamin C (C.H.O.) is a titration with potassium iodate (KIO). Potassium iodate is used as a titrant and is added to an ascorbic acid solution that contains strong acid and potassium iodide (KI). Potassium iodate reacts with excess potassium iodide, liberating molecular iodine (12): [1] KIO, + 5KI + 6H 31, +6K...
ascorbic acid (vitamin C, MM= 176.126 g/mole) is a reducing agent, reacting as follows: C6H8O6 ----> C6H6O6 + 2H+ + 2e- the concentration of ascorbic acid can be determined by oxidation with a standard solution of I2 (2 I- ---> I2 +2e-). A 200.0 mL sample of citrus fruit drink is acidified and 10.00 mL of 0.0500 M I2 is added. after the reaction is complete, the excess I2 is titrated with 38.62 mL of 0.0120 M Na2S2O3 according to...
Question 10 of 40 Question 10 2.5 points Save Answer 18.71 ml of an aqueous aluminum nitrate, Al(NO3)3 , solution is applied to the top of a column filled with a cation exchange resin in the protonated form. The column is then rinsed out and the nitric acid generated by the exchange of aluminum ions for protons is collected. It is found 43.42 ml of 0.2147 M NaOH is needed to titrate the acid. Calculate the mols of nitric acid...