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2. A 0.1000 g sample of KBrO3 was dissolved in dilute acid and treated with an excess of KI. BrO3 +91 +6H+ → Brº+ 313 + 3H20
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Answer #1

Boz &gi + 6H I mole mole af kpr 03 = Br +31 - + 3H₂O - 3 mole gram molarmoSS . 1678/mol = .005 989 =1006 mole KB.Oz = .006 mo

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