the variance of length of stay at a local hospital is 25. the standard deviation is...
the variance of length of stay at a local hospital is 25. the standard deviation is 5, and this is how each value differs on average from the mean. TRUE or FALSE?
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Yes, it is .
It is "on average" how much a data point is deviating from the true mean
This seems to be the message conveyed by the sentence in the question " this is how each value differs on average from the mean". Please remember that the word "differs on average" is very important.
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the variance of length of stay at a local hospital is 25. the
standard deviation is...
If the variance of the length of stay of a patient in a hospital is 25...
If the variance of the length of stay of a patient in a hospital is 25 days, the standard deviation is how many days?
Consider a large hospital that wants to estimate the average length of stay of its patients....
Consider a large hospital that wants to estimate the average length of stay of its patients. The hospital randomly samples n = 100 of its patients and finds that the sample mean length of stay is 4.5 days. Assume that the standard deviation of the length of stay for all hospital patients is 4 days. Find a 95% confident interval for true mean length of all hospital patients. O (3.84.5.16) O (3.72,5.28)
5. The management of Recover Fast Hospital (RFH) claims that the average length of stay in...
5. The management of Recover Fast Hospital (RFH) claims that the average length of stay in their hospital after a major surgery is less than the average length of stay at General Hospital (GH). Independent random samples were selected and the following statistics were calculated. Sample size Mean (in days) Standard deviation (a) RFH 45 0.6 0.5 GH 58 4.9 0.6 (1POINT) Formulate the hypotheses но. mu1-mu2 a mu1<mu2 Compute the test statistic Using the p-value approach, determine if the...
Question Help The standard deviation of the lengths of hospital stay on the intervention ward is...
Question Help The standard deviation of the lengths of hospital stay on the intervention ward is 78 days. Come parts through (c) below a. For the variable length of hospital stay." determine the sampling distribution of the sample mear for samples of patients The standard deviation of the sample mean is days. (Round to four decimal places as needed.) b. The distribution of the length of hospital stayis right skewed Does this invalidate your result in part (a? Explain your...
The standard deviation of the lengths of hospital stay on the intervention ward is 7.4 days....
The standard deviation of the lengths of hospital stay on the intervention ward is 7.4 days. Complete parts (a) through (c) below. a. For the variable "length of hospital stay," determine the sampling distribution of the sample mean for samples of 91 patients. The standard deviation of the sample mean is sigma Subscript x overbarequals 0.7757 days. (Round to four decimal places as needed.) b. The distribution of the length of hospital stay is right skewed. Does this invalidate your...
the average length of a hospital stay is 4.8 days. if we assume the lengths of...
the average length of a hospital stay is 4.8 days. if we assume the lengths of hospital stays are normally distributed with a standard deviation of 1.499, then 10% of hospital stays are longer than how many days?
Suppose you monitor quality assurance for a local hospital and want to estimate the average length...
Suppose you monitor quality assurance for a local hospital and want to estimate the average length of stay (LOS) at your hospital. You take a random sample of 30 patients and find that the average LOS is 3.8 days with a sample standard deviation of 1.2 days. What is the 95% confidence interval for the population average length of stay? Select one: (3.43, 4.17) (3.35, 4.25) (3.20, 4.40) (3.61, 3.82) none of these are correct
Name: Wit: SAMPLING DISTRIBUTION EXERCISE The average length of a hospital stay in general or community...
Name: Wit: SAMPLING DISTRIBUTION EXERCISE The average length of a hospital stay in general or community hospitals in the United States is 6 days Assume that the population standard deviation is 7.7 days. A simple random sample of 49 patients is drawn from this population. 1. What is the sampling distribution of the sample mean? 2. What is the probability that the average length of stay for this group of patients will be no more thana week? 3. What is...
(3) Suppose the length of stay in a chronic disease hospital of a certain type of...
(3) Suppose the length of stay in a chronic disease hospital of a certain type of patient has the mean of 60 days with a standard deviation of 15 days. It is reasonably to assume an approximately normal distribution of the lengths of stay (a) If one patient is selected from this group at random, what the probability that this patient will have a length of stay between 50 and 90 days? at is selected from this group at random,...
Suppose we measure length of hospital stay (in days) for patients undergoing a particular surgical procedure....
Suppose we measure length of hospital stay (in days) for patients undergoing a particular surgical procedure. The mean is 3 days with a standard deviation of 3.2 days. (a) [10 points] If a sample of 35 patients is selected, what is the probability that their mean length of stay is less than 2 days? (b) [10 points] If a sample of 35 patients is selected, what is the probability that their mean length of stay is more than 5 days?
Consider a large hospital that wants to estimate the average length of stay of its patients. The hospital randomly samples n = 100 of its patients and finds that the sample mean length of stay is 4.5 days. Assume that the standard deviation of the length of stay for all hospital patients is 4 days. Find a 95% confident interval for true mean length of all hospital patients. O (3.84.5.16) O (3.72,5.28)
5. The management of Recover Fast Hospital (RFH) claims that the average length of stay in their hospital after a major surgery is less than the average length of stay at General Hospital (GH). Independent random samples were selected and the following statistics were calculated. Sample size Mean (in days) Standard deviation (a) RFH 45 0.6 0.5 GH 58 4.9 0.6 (1POINT) Formulate the hypotheses но. mu1-mu2 a mu1<mu2 Compute the test statistic Using the p-value approach, determine if the...
Question Help The standard deviation of the lengths of hospital stay on the intervention ward is 78 days. Come parts through (c) below a. For the variable length of hospital stay." determine the sampling distribution of the sample mear for samples of patients The standard deviation of the sample mean is days. (Round to four decimal places as needed.) b. The distribution of the length of hospital stayis right skewed Does this invalidate your result in part (a? Explain your...
Name: Wit: SAMPLING DISTRIBUTION EXERCISE The average length of a hospital stay in general or community hospitals in the United States is 6 days Assume that the population standard deviation is 7.7 days. A simple random sample of 49 patients is drawn from this population. 1. What is the sampling distribution of the sample mean? 2. What is the probability that the average length of stay for this group of patients will be no more thana week? 3. What is...
(3) Suppose the length of stay in a chronic disease hospital of a certain type of patient has the mean of 60 days with a standard deviation of 15 days. It is reasonably to assume an approximately normal distribution of the lengths of stay (a) If one patient is selected from this group at random, what the probability that this patient will have a length of stay between 50 and 90 days? at is selected from this group at random,...
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