Construct the 2 by 2 table for CMZ test the gold standard when a cutoff of >41 units is used for classification ( equal or greater).
![A new, rapid blood test [CMZ test] was developed to test febrile patients for viral infection. You are asked to assist with the validation. The CMZ assay was run on 789 febrile people who arrived at the local public hospital seeking medical care. Samples from patients were divided into Opox infected and not infected using a combination of PCR and virus isolation methods, which can be considered a gold standard. eet res(ity units on bto 789 people. Gold standard No Infection Qpox Infection CMZ Test result (Units) 0-20 21-40 41-60 61-80 81-100 Total number of patients No. patients No. patients 359 186 75 0 32 41 89 167 0 622 1. Construct the 2 by 2 table for CMZ test versus the gold standard when cutoff of 241 units is used for classification (equal or greater is positive)](http://img.homeworklib.com/questions/7f84d8c0-70ac-11ea-950f-89176dc465b5.png?x-oss-process=image/resize,w_560)
There are 6steps for creating 2 by 2table for CMZ test:
- create a observation frequency
- calculate the column and row total
- calculate the expected frequency
- calculate the sum difference
- compare the values
In gold standard number of not infected patients 359 +186+75+2+-0= 622
Total number of Qpox infection Patient 0+5+32+41+89 = 167
0-20=359
21-40= 191
41-60 = 107
61-80 = 43
81- 100= 89
Total = 789
They used cutoff>41 units for the combination of CMZ test and gold standard..it was normal after cutoff >41units..
It is equal
Construct the 2 by 2 table for CMZ test the gold standard when a cutoff of...
Test No. 3 ( (Form B)Math 100 Spring 2019 I. Multiple-choice (Circle the letter of your answer): Questions No. 1 through No. 5 refer to the following: A continuous s has a normal distribution with the mean of 80 and standard deviation of 15 random variable x (1) The mode of the variable s is A 80 (B) 15 (C) 40 (D) Unknown (2) The z-score for the mode of x : (A) I (3) The p (B) 0.S ity...
does anyone know what High and low group means in this
context? i really do not understand this article so anyone that
does please explain it to me and what the hugh and low group mean
in the figures.
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