Question

can you help answer this question according to the two other pictures?

Procedure: Measure and dispense 0.6 ml of a 4.4 M solution of sodium methoxide in methanol and of ethanol into a 5 mL reaction vial. Add 2.5 mmol of acetaminophen (-0.378. Set up for reflux in the rume hood and bring reaction to reflux for 15 minutes (solvent is boiling and vapors are condensing on condenser). After 15 minutes directly through the top of the condenser tube, carefully add 0.3 ml of my iodide. Continue to reflux for another 45 minutes After 45 minutes, slowly add 2 mL of water down through the top of the condenser while the reaction mixture is still hot. If a precipitate forms, heat until it dissolves. Turn off the heat, carefully raise the condenser, and pour the reaction mixture into a small beaker and add an additional 2 ml of water. Cool the beaker in an ice bath until crystallization is complete. Collect the crystals by vacuum filtration. Dry under the heat lamp and record the mass of the crude product. Take a melting point and a TLC of the crude material. Time permitting, recrystallize the product using ethanol and water in a mixed solvent procedure. Dry the crystals. Record the mass and take a TLC of the pure product Cleaning Up: The solvent from the crystallization should be placed in the organic solvents waste container in 60:40 eth Ace / Hexane solvent A-acetaminophen P = Phenacitin Ccrude) 0:46,4299 46, 739 a :: 0,3108 final acetaminophon S: 0.3789 0,378 g initial acetaminophen

Answer 1

mass of Acetaminophen = 0.3789. molar mass Q Aataminophen= 151.169/mol. number of moles of Acetaminophene mass - 0.31880 .0025 ml - nolar mass 151 16g/ and molarity of Sodiam melhoride = 4:47 volume of sodium methoxide - 0.6mL@ 0.6mhxlL...000 looomt number of moles 4 sodiam methoride- molarityx volume int =4.4 md), X0.0006% = 0.00264 miles amber of moles of sodium methoxide = 0.00264 moes volume of Ethyl beomide = 0.36 ML Density of Ethyl bromide = 1.469/m2 mass of ethyl bromide = volumex Density = 0.3 mL Xer469 | ml mass of ethyl bromide = 0.438 g molar maxs of ethyl blomide= 108.966 g/mol amber of moes of ethyl beomide = mass 0.439 mdomass 108.9668/ml Number of moles of chyl bromide = 0.003946 moles Among z reactants Acetaminophen €0.0025 moles) sodium methoaide (0.00264 moles), ethyl bromide € 0.003946 holes Acetaminophen has least number of moles. So Acetamino phen is limiting reagent.

limiting reagent is the reagent which has Less number of moles we have to calculate yield based on limiting reagent. Theoretical xield mass of readant molar mass of - Product . - molar mass of rectant molar mass of product Phenaatin 179.219 g/mol Theoutical xield = 0.3788 x 179.219gt and 151-16 Bhad Theoretical xield = 0.44816 g. experimental xield = 0.3log. However you mentioned as Finalactaminophen. I think it is product band on this %. Xield = experimental Xield, 100 = 0.44816g xipo - Theoretical xield 0.3log 0.3109 vioo G9-17:/. 0.448169 17. Xield of crude product = 69.17% -