Molar mass of BaCl2,
MM = 1*MM(Ba) + 2*MM(Cl)
= 1*137.3 + 2*35.45
= 208.2 g/mol
use:
mass of BaCl2,
m = number of mol * molar mass
= 15 mol * 2.082*10^2 g/mol
= 3.123*10^3 g
Answer: 3.12*10^3 g
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