Question

For AgCl, at 25°c, Ksp=1.6x10-10. For KNO3 solutions: 0.050 0.1000.150 0.200 YAg+ 0.8105 0.7565 0.7199 0.6914 Yr 0.8217 0.7776 0.7503 0.7306 Determine the molar solubility of silver chloride in 0.150-M potassium nitrate solution. Submit Answer Incorrect. Tries 1/5 Previous Tries

3.47 is wrong

Answer 1

0.150 M KNO3 Sagt = 0.7199 and scu - 0.7503 + Ag cl(s) à Ag + (aq) + ci(ar) S (M) S (M) Кез да + au- Ksp = {Agt] [cr] x 8 Ag+ xda- Ksp = sxs x bagt & bar 1.68 10-10 = 5 x 0.71gg x 0.7503 s = 1.72 x 10-5 (M) molar Solubility of Aga = 1.72 x 1075 (m) .