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Given that, for AgCl, at 25°C, K = 1.6x10-10: What is the solubility (g/mL) of AgCl in water at 25°C? 1.26 x 10-5 M You haveGiven: Ksp(Ag2Cro4) = 1.2x10-12 Ksp(BaCro4) 2.1x10-10 For a solution which is initially 0.002 M in Ba2 and 0.002 M in Ag*, it

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Answer #1

- Let the solubility of Agel be s (M) Agel (aq) Ag+ (aq) + ci(99) SCM) IS(M) SCM) ... Ksp (Agut) = [Ag+][u] = s2 on s² = 1.68

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