Here we have data:
Traditional Lecture | Distance |
36 | 43 |
31 | 31 |
35 | 44 |
30 | 36 |
33 | 44 |
37 | 35 |
46 | |
43 |
Here we calculate by EXCEL.
a) - 1
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Traditional Lecture | 6 | 202 | 33.667 | 7.867 | ||
Distance | 8 | 322 | 40.25 | 29.643 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 148.60 | 1 | 148.60 | 7.22 | 0.0198 | 9.33 |
Within Groups | 246.83 | 12 | 20.57 | |||
Total | 395.43 | 13 |
a)-2
The critical value of F = 9.33
b) Here we have
F = 7.22
t^{2} = F
t = 7.22
t = 2.687
c) Fail to reject H_{o. There is not difference in the mean scores between lecture and internet-based formals.}
When only two treatments are involved, ANOVA and the Student's t test (Chapter 11) result in...
When only two treatments are involved, ANOVA and the Student’s t test (Chapter 11) result in the same conclusions. Also, for computed test statistics, t2 = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of 6 students who took the course in the normal lecture format. The other group of 8 students took the course as a distance course format. At the end...
When only two treatments are Involved, ANOVA and the Student's ttest (Chapter 11) result In the same concluslons. Also, for computed test statistics,迢= F To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a hlstory course were divded Into two groups, one consisting of 6 students who took the course In the normal lecture format. The other group of 8 students took the course as a distance course format. At the end of the course,...
When only two treatments are involved, ANOVA andthe Students ttest (Chapter 11) result in the same conclusions. Also, for computed test statistics, F. To demonstrate this relationship use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of 6 students who took the course in the normal lecture format. The other group of 8 students took the course as a distance course format. At the end of the course, each...
Question: When only two treatments are involved, ANOVA and the Student’s t test (Chapter 11) result in the same conclusions. Also, for computed test statistics, t2 = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of 6 students who took the course in the normal lecture format. The other group of 8 students took the course as a distance course format. At the...
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Chapter 12 Extra Practice (Optional 1 03 pon When only two treatments are involved. ANOVA and the Student's test (Chapter 19 result in the same conclusions. Also, for computed test statistics, F To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of 6 students who took the course in the normal lecture format. The other group of students took the course as a distance course...
CH13 Q9 A researcher conducts a two-way ANOVA test with interaction and provides the following ANOVA table a. Find the missing values in the ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "MS" to 4 decimal places and "F' to 3 decimal places.) ANOVA Source of Variation Sample Columns df MS 770.76 12,351.18 55.10 693.74 13,870.78 F Factor B- F Factor A F Interaction- 2 MSB 1MSA- Within 12 MSE- 17 Total
Exercise 13-45 Algo A researcher conducts a two-way ANOVA test with interaction and provides the following ANOVA table. a. Find the missing values in the ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "MS" to 4 decimal places and "F" to 3 decimal places.) ANOVA Source of Variation SS df MS F p-value Sample 776.84 2 MSB = F Factor B = 0.010 Columns 12,425.44 1 MSA = F Factor A = 4.57E-09 Interaction 56.25 2...
9 A researcher conducts a two-way ANOVA t with interaction and provides the following ANOVA table a. Find the missing values in the ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "MS" to 4 decimal places and " places.) to 3 decimal 12233 b. At the 5% significance level, can you conclude that there is an interaction effect? es since the p-nlue for interection is grester ha he signiscance No-since he puue for inneracion is greoter...
newconnect.mheducation.com Student Homa Chapter 13 Quiz A Gat Hamework Halp With Chagg Study C Salved: An accounting prafassor wants o k Chapter 13 Quiz A Help Save & ExitSubmit An accounting professor wants to know if students perform the same on the departmental final exam irrespective of the accounting section they attend. She randomly selects the exam scores of 51 students from six sections. A portion of the output from conductinga one-way ANOVA test is shown in the accompanying table....