A primary key must be
1. unique and cannot be null
2. unique and can be null
3. duplicated and cannot be null
4. duplicated and can be null
| A primary key must be unique and cannot be null |
| A primary key is a field used to identify records uniquely in a database. |
| A primary key must always have a value and cannot be left blank. |
| Option 1 is correct |
A primary key must be 1. unique and cannot be null 2. unique and can be...
CREATE TABLE person ( pid INTEGER NOT NULL ,pname VARCHAR(30) NOT NULL ,PRIMARY KEY (pid) ); CREATE TABLE organization ( oid INTEGER NOT NULL ,oname VARCHAR(30) NOT NULL ,PRIMARY KEY (oid) ); CREATE TABLE venue ( vid INTEGER NOT NULL ,area CHAR(1) NOT NULL ,capacity INTEGER NOT NULL ,PRIMARY KEY (vid) ); CREATE TABLE calendar ( vid INTEGER NOT NULL ,date DATE NOT NULL ,price NUMERIC(6,2) NOT NULL ,PRIMARY KEY(vid,date) ,FOREIGN KEY(vid) REFERENCES venue(vid) ); CREATE TABLE event ( eid...
1. Key resources of sugarbear hair company ( what unique steategic assets must the business have to complete.) 2. key activities of sugarbear hair company ( what can the company not do so it can focus on its key activities?) 3. Cost structure of sugarbear hair company. ( what are the business major cost drivers? how are they linked to revenue.)
Which of the following describes referential integrity? A. A Primary Key of a relational table must not contain a null value B. One fact must not be in multiple places C. The value for a foreign key attribute must either be null or match the one of the data value of that attribute in the table in which the attribute is a primary key D. Referential Integrity is a principle that prevents the use of redundancy, avoids null values and...
A database imposes several requirements on the structure of tables. Which of the following is not one of those requirements? A foreign key must be unique. A primary key must be unique. A primary key cannot be null (blank). A foreign key must be a primary key from another table.
Database Design and Management: The percent sign (%) and asterisk (*) symbols can be used with the LIKE comparison operator to create a search pattern. True or False? When translating an arc relationship to a physical design, you must turn the arc relationships into foreign keys. Assuming you are implementing an Exclusive Design, you must also create two Unique Key Constraints to ensure the Arc is implemented correctly. True or False? The explanation below is a User Defined integrity rule...
key attribute depends upon the whole primary key. 8. The result of normalization is that every A) Candidates B) Unique C) Primary D) Non-primary key attribute depends upon the whole primary key. 9. The result of normalization is that every A) Candidate B) Unique C) Primary D) Non-primary to show the 10. Increasingly, developers are using tools that can quickly create screen mockups, referred to as placement of information elements on a screen and the space needed for each element....
CREATE TABLE Gender ( gender CHAR(1), description VARCHAR(10), PRIMARY KEY (gender) ); CREATE TABLE People ( ID INT, name VARCHAR(50), gender CHAR(1), height FLOAT, PRIMARY KEY (ID), FOREIGN KEY (gender) REFERENCES Gender (gender) ); CREATE TABLE Sports ( ID INT, name VARCHAR(50), record FLOAT, PRIMARY KEY (ID), UNIQUE (name) ); CREATE TABLE Competitions ( ID INT, place VARCHAR(50), held DATE, PRIMARY KEY (ID) ); CREATE TABLE Results ( peopleID INT NOT NULL, competitionID INT NOT NULL, sportID INT NOT NULL,...
QUESTION 6 Which of the following statements best illustrates the "Key" constraint? The schema MUST be created before tables are added A primary key MUST NOT have duplicate values A foreign key value MUST have a value already present as a primary key in another table (or be NULL) A primary key value MUST have a value QUESTION 7 Which of the following statements best illustrates the "Referential Integrity" constraint? The schema MUST be created before tables are added A...
A foreign key value must exist in the table where it is a primary key. True? False?
Given (Oracle) SQL Script " CREATE TABLE Members( MemberID NUMBER(4) NOT NULL PRIMARY KEY, MFirst VARCHAR(25) NOT NULL, MLast VARCHAR(25) NOT NULL, Street VARCHAR(64) NOT NULL, City VARCHAR(25) NOT NULL, State VARCHAR(2) NOT NULL, ZipCode NUMBER(5) NOT NULL, CreditLimit NUMBER(7,2) NOT NULL, Gender VARCHAR(1) NOT NULL CHECK (Gender IN('F','M')) ); CREATE TABLE Employees( EmployeeID NUMBER(3) NOT NULL PRIMARY KEY, EFirst VARCHAR(25) NOT NULL, ELast VARCHAR(25) NOT NULL, ...