Question

Physics 1 2D Kinematics Activity 10 Name (Print) Section: A 90kg hockey player is skating at 12 m/s directly up the ice toward the opponents' goal when his team loses the puck, and he has to make a sudden change in direction to 12 m/s in the direction 60" away from skating backwards toward his own goal If he is to complete the turn within three quarters of a second, how much (constant) force must be applied to change his motion 60 [FLIP THE WORKSHEET OVER IF YOU NEED SOME HINTS!

Answer 1

Initial momentum in x dir = 0 initial momentum in y dir = mv final momentum in x dir = -m v sin 60 degree final momentum in y dir = -m v cos 60 degree charge in momentum in x dir (delta P_x) delta P_x = -m v sin 60 degree - 0 = -0.86 m v charge in momentum in y dir delta P_y = -m v cos 60 degree - m v delta P_y = -1.5 m v delta p (charge in momentum) = squareroot delta P_x^2 + delta P_y^2 delta P = 1.732 m where m = 90 kg, v = 12 m/s delta P = 1870.614 kg m/s as By Newton's law F_avg = delta P/ delta t = 1870.614/1/4 F_avg = 7482.45 N