Excel' has functions for finding x-values or z-values associated with a cumulative probability from a normal distribution. This cumulative probability must be an upper-tail - more than - probability.
P(Z < z ) = p
to calculate z
=normsinv(p)
for example for p = 0.95
z = normsinv(0.95)
= 1.645
however you want z-critical value for confidence interval of 100 (1-p) %
then you have to write
normsinv(1 -p/2)
for example for 95% confidence
=normsinv(0.975)
Excel' has functions for finding x-values or z-values associated with a cumulative probability from a normal...
1. Assuming the Standard Normal Distribution, USING EXCEL find: a. What is the probability of Z < than -1.75? b. What is the probability of Z > than 1.00? c. What is the probability of Z between 1.00 and 2.00? d. 15% of the cumulative probability is above what value for Z? e. 95% of the cumulative probability is below what value for Z? f. What is the probability of Z<-2.00 OR X> 2.00? ...
1) Given a standard normal distribution, find the probability of having a z score higher than 1.67 ```{r} ``` 2) Given that test scores for a class are normally distributed with a mean of 80 and variance 36, find the probability that a test score is lower than a 45. ```{r} ``` 3) Given a standard normal distribution, find the Z score associated with a probability of .888 ```{r} ``` 4) Find the Z score associated with the 33rd quantile...
In a standard normal distribution, find the following values: The probability that a given z score is less than -2.67 The probability that a given z score is between 1.55 and 2.44 The z scores that separates the most inner (middle) 82% of the distribution to the rest The z score that separate the lower 65 % to the rest of the distribution
MUST use the NORM.DIST() or NORM.INVO) Normal Distribution functions in Excel. Provide your final answer rounded to 4 decimal places in the yellow highlight cell. Problem (i): The average credit card debt for college seniors is $3262. The debt has a normal distribution with a standard deviation of $1100. (4 points) a) What is the probability that a randomly selected college senior owes more than $4000? b) What is the probability that a randomly selected college senior owes between $4000...
The variable Z has a standard Normal distribution A. find the number z that has cumulative proportion 0.88 B. Find the number z that the event Z > z has proportion 0.12
You will be finding probabilities using excel. Use the Excel instructions for Binomial Distribution (=BINOMDIST(x, n, p, true or false)) False is equivalent to binompdf. True is equivalent to binomedf. State which probabilities are unusual. a.) P(x <6), n = 20, p= .8 b.) P(x < 16), n = 20, p=.15 c.) P(x> 14), n = 30, p = .35 3.) Twelve percent of people in the US eligible to donate blood actually do. You randomly section 15 eligible blood...
How do you put the answer in a excel format These z values can be obtained using Excel’s NORM.S.INV function or by using the standard normal probability table in the text. a. The z value corresponding to a cumulative probability of .2119 is z = -.80. NORM.S.INV(.2119) b. Compute .9030/2 = .4515; z corresponds to a cumulative probability of .5000 + .4515 = .9515. So z = 1.66. NORM.S.INV(.9515) c. Compute .2052/2 = .1026; z corresponds to a cumulative probability...
Q.1) Z is the standard normal variable. Use table 1 to determine
the required probability to four decimal places. Answers should be
given in the form 0.xxxx.
P(Z < -3.07)
Answer:
Q.2) X is a random variable which is normally distributed with a
mean of 99.01 and a standard deviation of 15.56. Use the Excel
function NORMINV to determine the required value of Xo to two
decimal places. Give your answer in the form xx.xx.
P(X < Xo) = 0.0344...
probability Q7 (4 marks) a) Creat a standard normal probability distribution plot for z-value for the range of (-3, 3) with increament of 0.5. b) Find the z value (to two decimal places) that cuts off an area in the upper tail section of the standard normal curve with probability of: 0.45 1) 0.0252) 0.053 ) 0.0054) 0.01 A) Answer Z-score probability -3 0.004431848 -2.5 0.0175283 -2 0.053990967 -1.5 0.129517596 -1 0.241970725 -0.5 0.352065327 0 0.39894228 0.5 0.352065327 1 0.241970725...
1 pts Z follows a standard normal distribution. What outcome, z (z-value), has a lower tail probability of 0.35?