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Centripetal Force/ Conservation of Energy A 500 kg car is on a roller coaster as shown below. - 35 m/s, find the normal force acting on the car at points A and B. 25 m 8.5 m
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Initially the car is on a height of 25m and its initial velocity is 35 m/s. The total energy of the car initially was the sum of both kinetic and potential energy Total energy - Initial kinetic energy+Initial potential energyo2 + mgh 428750 All of this total energy will become kinetic energy at point A. So we can find out the velocity of the car at point A as 428750- mu2 -× 500 × u2 after solving for v we get, $v-41.41$m/s Now at point A, there are three forces that are acting on the car, the gravitational force (mg), the normal force (n) and the centripetal force ( my 500 x 41.412 8.5 n 500 9.8 + n 105769.88N for point B there is an increase in potential energy because the car is now at height 17m from the ground and also at this point the gravitational and normal force are along the same direction (downward) and centripetal force is in upward direction. total kinetic energy of the car at B will be KE-428750-500 × 9.8 × 17 325450 from this kinetic energy the velocity will be 325450mv from this the velocity will be v- 37.17 m/s now to find the normal force

mu2 n + mg mv n 76371.1121

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