![Part 3 use trial 1 and 3 Trist I - 0.0093 M 0.ooogom 0.0000 28 M/S trial 3 = 0.0023 M 0.0018 M 0,0000 S2 m/s [103] [5,0}]; in](http://img.homeworklib.com/questions/2156b060-70ed-11ea-9d54-85ff092fc049.png?x-oss-process=image/resize,w_560)
part 3,4 and 5 please! Rate is defined as the change in S205 over time. Once...
Part 3,4 and 5 please!
Question #1 Rate is defined as the change in [S2052-] over time. Once the blue color appears, we assume [S2052-) = 0 M, so we have: Initial rate of reaction = -d[S205] = -(0-[S205 dt initial) - [S2052 Jinitial time dt Below are your data for trials 1-6 of Lab 7. Enter the initial rate for each trial. [S2052-Jinitial Time Initial rate 2.8x10-5 M/s Trial 1 .00090 M 32 s Ok Trial 2 .00090 M...
3,4,5!!! please
Question #2 Here are your data for trials 1-4 of Lab 7: [103 initial (S203 Jinitial Initial rate Trial 1 .0023 M 1 .00090 M .000028 M/s Trial 2 .0047 M .00090 M .000069 M/S Trial 3 .0023 M .0018 M .000052 M/S Trial 4 .0047 M .0018 M .000058 M/s The order with respect to 10, should be an integer (either 0, 1, or 2). Let's determine it using two sets of data: Part 1: Use the...
Question #5 Here are the relevant data to determine the activation energy of the reaction. Rate constant (units not shown) Temperature (K) .13 293 0.11 308 Use the data above to determine the activation energy of the reaction? 83 kJ/mol Submit This value is not correct. Please check your calculations and try again. Question #6 Here are your data for trial of Lab 7 (the trial at room temperature without the catalyst): [103 initial (S203 initial Initial Rate .0023 M...
question 5,6 part 1 and 2 please
Question #5 Here are the relevant data to determine the activation energy of the reaction. Rate constant (units not shown) Temperature (K) .13 293 0.11 308 Use the data above to determine the activation energy of the reaction. -3628 kl/mol Submit Please enter your results to the correct precision. Question #6 Here are your data for trial of Lab 7 (the trial at room temperature without the catalyst): [103 initial (S2032 Jinitial Initial...
Method of Initial Rates Practice: You've been tasked with finding the rate constant, k, of a reaction that has the following rate law: rate = k [E]y [F] Under conditions where [F]>>[E] such that [F] is a constant, you measured the rate of the reaction at four different initial concentrations of [E] and calculated the initial reaction rate of each reaction. The data are given below. Trial [E] (× 10-6 M) [F] (M) Initial Rate (× 10-6 M/s) 1 10.0...
The reaction 2NO(g) + Cl2(9) - 2NOCI(9) was studied at a constant temperature and the following results were obtained. 2.3 [NO]initial (Cilinitial Initial rate (M/min) 0.44 M 0.21 M 0.44 M 0.42 M 0.88 M 0.42 M 4.6 Rate is defined as the change in (CI) over time. Part 1: What is the order of the reaction with respect to NO? 2 Submit OK Part 2: What is the order of the reaction with respect to Cl? 1 Submit OK...
For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The following data were collected: Trial [A] (M) [B] (M) [C] (M) Initial rate (M/s) 1 0.40 0.40 0.40 1.2×10−4 2 0.40 0.40 1.20 3.6×10−4 3 0.80 0.40 0.40 4.8×10−4 4 0.80 0.80 0.40 4.8×10−4 Rate law equation The rate of a chemical reaction depends on the concentrations of the reactants. For the general reaction between Aand B, aA+bB⇌cC+dD The dependence of the reaction...
Name 3. O:o N-o он ONPG A scientist wants to measure if a test subject can digest lactose. This time, she uses 0.100 M ONPG (a harmless lactose alternative), which in the presence of constant (enzyme). forms a yellow product. You allow the reaction to proceed untif the yetlow product is vivid enough to observe, and vou calculate the initial rate. Data Initial rate (not average) 1.64 Mimin 3.66 M/min point ONPG 0200M 0.300 M 0.400 M 0500 м 0...
Question #5 In this question you will use your values from questions 2 and 3 to determine the value of AS° assuming the equilibrium constant, K, is equal to the concentration of urea in the saturated solution. Part 1: Determine the values of AS° in J/Kmol in both trials by assuming K = [urea). Trial #1 Trial #2 ASO J/Kmol This result is out of range. J/Kmol This result is out of range. Submit Check your answers. Part 2: Determine...
For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The following data were collected: Trial [A] (M) [B] (M) [C] (M) Initial rate (M/s) 1 0.40 0.40 0.40 1.2×10−4 2 0.40 0.40 1.20 3.6×10−4 3 0.80 0.40 0.40 4.8×10−4 4 0.80 0.80 0.40 4.8×10−4 Rate law equation The rate of a chemical reaction depends on the concentrations of the reactants. For the general reaction between A and B, aA+bB⇌cC+dD The dependence of the...