Question

Please help.

What is the [H0] and pH of the solution that result when 35.0mL of 0.020M HNO is mixed with 35.0mL of 0,020M NH3 ?

Answer 1

moles of N H2 = Volume x concentration = 354103x: 0.020 = 0.0007 mo) Moles of HNO3 = volume x concentration E 35X10PX0.020 = 0.0007 moi. Nitz + HNO3 NHANO 3 hores OL.NH3 = moles of N HNO3 Total volume = 35+35 = 70 m -0.070 L. concentration 06 NHut.z moles Volume 0.0007 010.70 z ooim.

lub know that, Ka = Cnc Hy) (N05) (NH3) 5.6x150 - 2100) : Cool-0) x = S 6 xuố'?-C6 Y18', 27516X180 %-516 voto on solving, we get, CH3 ot] =x = 714 x 106m. 1-30+) = 7.47166m PH = -log[ipot) =-10967147176) 2-65113) [PH = 5:13