Question

5.00 mL stock 5.00 mL Dilution A 5.00 mL Dilution B + 45.0 mL Water + 45.0 mL Water + 45.0 mL Water O b lo Dilution C Dilution A Dilution B Example #5. Solution A is prepared by diluting 1.00 mL of 0.160 M CaCl2 to 50.0 mL. Solution B is prepared by diluting 10.0 mL of Solution A to 500.0 mL. What is the concentration of CaCl2 in Solution B? O lodno tlo iz obdobimo t 100 babe blood O rolozhit ad to tom b () bolto lonto000.0 to liw not 02 nomi bi lo H.2.0 dislololo

Answer 1

takou Initial concentration of Call = 0.160m Then ime of this solution and diluted to some with water. Then New conch of Cally can be found using relation Min = rizky M, initial conch V = Initial volume un volume taken M₂= Final conch v₂ = final volume I co conch of Cally in solution A is 0-160 X 1 = M₂ X 50 M = 0.160 160 = 0.0032 My so conch of cally in son A is solution B is prepared by Now 0.0032 M diluting some of solution of A to 500 ml. Now My = 0.0032M; V = 10 me Mz-?; V2 = Store using relation again M, N = M2V . 0.00 32 X10 M2 X 500 M2 = 0.032 = 614 xid-S M E conch of call, in solution B = 6.48155m - So