Homework Answers
Mass of first isotope(M1) = 68.9 amu
Percent natural abundance of the first isotope =60.4%
Mass of second isotope(M2) = 70.9 amu
Percent natural abundance of the second isotope =39.6%
The formula to calculate the average atomic weight of the element is as follows:
Average atomic weight = [(M1 x % abundance of first isotope) +(M2 x % abundance of second isotope)]/100
Average atomic weight = [(68.9 amu x 60.4 %) +(70.9 amu x 39.6%)]/100
Average atomic weight = 69.7 amu
Thus, the atomic weight of the element is 69.7 amu [ 3 S.F]
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