Question

all answers please

(25%) Problem 1: A mass m= 1.7 kg is at the end of a horizontal spring on a frictionless horizontal surface. The mass is oscillating with an amplitude A = 1.5 cm and a frequency f= 1.2 Hz. A 20% Part (a) Write an equation for the spring constant k. A 20% Part (b) Calculate the spring constant k, in Newtons per meter. A 20% Part (c) Write an equation for the total mechanical energy, E, of the motion. Your expression should be in terms of the variables in the original problem statement. 20% Part (d) Calculate the total mechanical energy E, in joules. > 20% Part (e) If the amplitude is doubled, what happens to the total mechanical energy? Choose the best answer E is halved. Grade Summary Deductions 0% It cannot be determined with the information provided. Potential 100% E remains unchanged. E increases by a factor of four. Submissions Attempts remaining: 4 E doubles. (25% per attempt) detailed view Submit Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback.

Answer 1

can K= mwe = m(ant. = m(anf)? =472 m f² Ub k= 46°x1.7 x (1.2)? = 96.6 NIM Ł mw²A² A=1.5cm =lis 10² m (C) E= Žm Canf2 A² = 2x² m f² ². (d) ez x 1.7 x (1.23?x Cl-5x102)2 = 1.09 x 10-2 J cel if a E → doubled (made a times) 4 times (as EXA²) E increases by factor of 4