Question

(8%) Problem 6: Amass m= 2.95 kg is at the end of a horizontal spring on a frictionless horizontal surface. The mass is oscillating with an amplitude A = 8.5 cm and a frequency f= 1.9 Hz 20% Part (a) Write an equation for the spring constant k. k(2fm Correct! 20% Part (b) Calculate the spring constant k, in Newtons per meter k= 420.4 Correct! 20% Part (c) Write an equation for the total mechanical energy, E, of the motion. Your expression should be in terms of the variables in the original problem statement. Grade Summary E = Deductions 06 100 Potential 7 8 Submissions a Attempts remaining: 10 45 е A 6 per attempt) detailed view 123 d f g h - 0 ND OBACKSPACE CLEAR m Submit Hint Feedback I give up! Hints: 096 deduction per hint. Hints remaining:3 Feedback: 1 deduction per feedback A 20% Part (d) Calculate the total mechanical energy E, in joules 20% Part (e) If the amplitude is doubled, what happens to the total mechanical energy? Choose the best answer

Answer 1

(a) ka mw2 = m (277)? - 4172 m2 © k = (20)2( 2.95 kg)(1:32) = 420-4 MIM . E = 1 KA² = (277)² m A² W E X 4204 x (00854)? - 1-525 ② E & A & A = 2A then I'= 46 It quadrupled . 2