Question

Reaction (draw the reaction scheme including starting material, reagents and expected product): OH NaBr H2SO4 3-phenylpropan-1-ol (3-bromopropyl)benzene Fill in the reagent table below as completely as possible: Chemical Name Mass/Volume Used Moles Chemical Properties State of Matter Safety from MSDS Detailed Procedure: (list all important steps of the reaction, separation, purification, and analysis; be very practical and detailed, include important observations)

Please, identify a procedure that will help make the product and purify it properly. Given 4 mL of starting material (alcohol) and as much necessary of other materials for the reaction. Using reflux, separatory funnel, distillation procedures. Listed below is what is provided.

1. Reflux: Sulfuric acid is provided at 9M. Include temperature and time of reflux, please.

2. Separation: sodium bicarbonate and water provided for extrication

3. Purification: Provided Sodium Sulfate

4. Distillation: What will be the distillate and what will remain in the pot?

Update: The reaction is provided above. 3-phenyl-1-propanol mixed with sodium bromide and sulfuric acid to produce 3-bromopropylbenzene.

Answer 1

Nab H250. Moc : 196.19 CH11B Mol. Wt: 199.09 2 Na + 3H2SO. 2 NaHSO4. Br + S02 2 H,0 Chemicals Mol. Wt Moles Density Mass Vol. 4ml 8.645 6.045 0 3-Phenylpropane-1-ol H.SO. NaBr 1.00 136.19 98.08 102.89 .02937 0.08811 0.05874 Mole ratio 1.0 3.0 2.0 State of Matter Liquid Liquid Solid - Since you have 9M H,SO, which is nearly 50% solution. It means 10ml of 9M H.SO, contains 5g of H,SO According to stoichiometric amount we required 8.64g of H2SO.. So we required 17.3 ml of 9M H2SO4 Procedure:- Arrange a 3neck round bottom flask equipped with water condenser, thermometer and place in heating bath Add 3-Phenylpropane-1-ol (4ml), followed by addition of 9M H.SO.(17.3ml) and NaBr (6.04g). He at the reaction massto reflux for 7-8hrs. Monitor the course of reaction by TLC If not complete then heat further till it completes. Neutralize the reaction mass by NaHCO, till pH 7. Extract the product by solvent extraction process using Ethyl acetate (10ml). Separate the layers by separating funnel. Collect the organic layer, dry over anhydrous sodium sulphate (1g) and filter. Collect the filtered organic layer and evaporate to dryness. Residue will be the product. (Theoretical yield = 5.845) Notes - The reaction generates in-situ bromine which will react with alcohol to give the desired product. The quantity mentioned here is according to stoichiometry. If some starting material remains unreacted, you need to change the amount of sulphuric acid and sodium bromide and also the reaction condition