I have an idea on how to do it but not entirely sure help?
I believe it's off the information based on this I'm
not to sure
Homework Answers
So answers are as below
Molarity is concentration i.e. no of moles divided by volume of solution in litres
If you titrate for the acid concentration & molarity of white vinegar then we will prove the commercial distilled white vinegar contains
5% acetic acid
molarity of approximately 0.8M .
The vinegar contains 5g acetic acid in 100mL of solution so 50g per L. 50g
CH3CO2H/60g/mol = 0.833 moles in 1 L
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I have an idea on how to do it but not entirely sure
help?
I believe...
so I'm struggling with how to calculate the average volume of the NaOH I'm not entirely...
so I'm struggling with how to calculate the average
volume of the NaOH I'm not entirely sure how to do that
Run 3 Run 1 Final Buret Volume(mL) 22.00nc 0.0 mc 22.00nC Run 2 26.00m 0.0 mc 26.0cm 21.05 me o.one 21.05 me Initial Buret Volume(mL) Volume NaOH Delivered (mL) Average Volume of NaOH (mL) Calculated molarity of diluted vinegar solution: Name: Name: F. Data and Calculations Molarity of standardized sodium hydroxide solution 0.09800 10:1 25.00mL Dilution factor for vinegar...
Following question: -Calulated molarity of diluted vinegar solution -Molarity of Commercial Vinegar (multiply by the dilution...
Following question:
-Calulated molarity of diluted vinegar solution
-Molarity of Commercial Vinegar (multiply by the dilution
factor
-Percent (mass/volume) of acetic acid in commefcial
vinegar
Data and Calculations Molarity of standardized sodium hydroxide solution Dilution factor for vinegar solution prepared in step 4 i 20 Volume of diluted vinegar titrated in each run Titrations: Run 3 Run 2 Run 1 G (o .00 ml Final Buret 22.20 Volume (mL) Initial Buret Volume (mL) 22.20 WL Volume NaOH 22.3 Delivered (mL)...
Need help someone please help me like right now.thank you in advance!!!!!! VALUE Volume original vinegar...
Need help someone please help me like right now.thank you in
advance!!!!!!
VALUE Volume original vinegar solution Volume diluted vinegar solution Dilution Factor Molarity of NaOH SD 5 ml DZAM TRIAL 1 TRIAL 2 TRIAL 3 HL 10.00mL 0.0 ML SolomL 15. lom 11. 5. 110. 20ml 5.10mL In 10.20m 15. Gou 5.20ml Volume of diluted vinegar sample used in each titration (mL) #2 Initial buret reading (mL) Final buret reading (ml) Volume of NaOH Moles of NaOH Moles of...
I need it right now, please help me?? PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The...
I
need it right now, please help me??
PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The vinegar solution must be diluted by a factor of 5 to be suitable for titration. 1. Obtain - 20 ml of the stock vinegar solution from the fume hood. 2. Using the 10-ml. pipet, pipet" 10 mL of the stock solution to a 50-ml volumetric flask. 3. Fill the volumetric flask to the calibration line with distilled water. Be sure not to go over...
I dont know how to do this exercise please ignore my answers ME General Chemistry I...
I dont know how to do this exercise please ignore my
answers
ME General Chemistry I Molarity of Acetic Acid in Vinegar: A Titration Experiment NaOH = 40.019/mols NaOH DATA AND CALCULATIONS STANDARDIZATION OF NaOH lesina Check the 2 (at least) trials O O O Check the 2 (at least) trials used to calculate the average molarity. Trial 1 Trial 2 Trial 3 Mass of KHP Moles of KHP 1991/ 37.50 m2 read - 1-0.72893 0 7599 0.75792- 16,59 Initial...
the volume, moles and average need to be calculated from the calculated numbers i got above...
the
volume, moles and average need to be calculated from the calculated
numbers i got above
the
molarity of NaOH is 0.2998M
DATE SECTION - B. Analysis of Vinegar average molarity of NaOH (from part A), M HC,H,O, (aq) + NaOH(aq) → H,O (1) + NaC,H,O, (aq) Trial 1 Trial 2 Trial 3 volume of vinegar, ml 10mL 10mL 10mL volume of vinegar, L initial buret reading, mL final buret reading, ml 0.25mL 0.11mL 0.32mL 30.01ML 31.5mL 28.50mL volume of...
question 6 UUTUUDIY Report Titration Run 1 Run 3 Name Laura A cense Run 2 Volume...
question 6
UUTUUDIY Report Titration Run 1 Run 3 Name Laura A cense Run 2 Volume of Vinegar Used o radac Concentration of NaOH 0.100 M 0.100 M 0.100 M 1.45 mL 1 1 19.68 ml 107.69 m2 Final Buret reading 19.68 m 36.78me lauo some Volume of NaOH Used 6.01sas 0.01710 0,ole 871 (Final Buret reading - 18.a I rolML 18h 16.87 Initial Buret reading) Calculations: 1. Calculate the number moles of base required to reach the endpoint for...
I need help calculating the mass percent and with the post lab question #2. Part 1...
I need help calculating the mass percent and with the post lab
question #2.
Part 1 Mass Initial | Final Vol Nall Moles concen. KPHCG (ML) I (m2) Used (m2) KHP (mol)/NaOH(M) 0.28470.00 13.60r 13.600 10.00- 0.1025 2 UZ + ZANT 13.600 24.45 1 10.85 0.001128 10.40 Aug NaOH Concentration (M):0.1032 Part2 Vinegar identification # 4 Vinegar sample date: (011/ Vol Vinegat Initial Final Yol NaOH Mol Acotic Mass Acctic Mass % Titr ULST I OML Used (ml) Acid (mol)...
Need help filling out the rest of the table, please. 1 M of NaOH 5% of...
Need help filling out the rest of the table,
please.
1 M of NaOH
5% of acidity of acetic acid (vinegar)
n out Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar 419 Volume of Vinegar Density 1.005 g/ml Initial NaOH volume in syinge OmL Final NoOH volume in syringe 5.8m Volume of NaOH Delivered i mL 3. b ?? Moles of NaOH Delivered Moles of Acetic Acid...
analysis of vinegar lab question help I'm trying to figure out how to find the molarity...
analysis of vinegar lab question help
I'm trying to figure out how to find the molarity of acid
the average molarity from naOH concentration is 0.252M
Advertised % Acetic Acid B. Analysis of Vinegar (Acetie Acid) Trial #1 Trial #2 Trial #3 8. Volume of vinegar Final buret reading 1.00ml 1.00 mi 1.00ml 6.40 ml. 13.4 me 20.2 mi. 0.00 m. 6.40ml 64 ml. 6.40 mi 7.00 ml. 13,80 ml, M - M 10. Initial buret reading 11. Volume of...
so I'm struggling with how to calculate the average
volume of the NaOH I'm not entirely sure how to do that
Run 3 Run 1 Final Buret Volume(mL) 22.00nc 0.0 mc 22.00nC Run 2 26.00m 0.0 mc 26.0cm 21.05 me o.one 21.05 me Initial Buret Volume(mL) Volume NaOH Delivered (mL) Average Volume of NaOH (mL) Calculated molarity of diluted vinegar solution: Name: Name: F. Data and Calculations Molarity of standardized sodium hydroxide solution 0.09800 10:1 25.00mL Dilution factor for vinegar...
Following question:
-Calulated molarity of diluted vinegar solution
-Molarity of Commercial Vinegar (multiply by the dilution
factor
-Percent (mass/volume) of acetic acid in commefcial
vinegar
Data and Calculations Molarity of standardized sodium hydroxide solution Dilution factor for vinegar solution prepared in step 4 i 20 Volume of diluted vinegar titrated in each run Titrations: Run 3 Run 2 Run 1 G (o .00 ml Final Buret 22.20 Volume (mL) Initial Buret Volume (mL) 22.20 WL Volume NaOH 22.3 Delivered (mL)...
Need help someone please help me like right now.thank you in
advance!!!!!!
VALUE Volume original vinegar solution Volume diluted vinegar solution Dilution Factor Molarity of NaOH SD 5 ml DZAM TRIAL 1 TRIAL 2 TRIAL 3 HL 10.00mL 0.0 ML SolomL 15. lom 11. 5. 110. 20ml 5.10mL In 10.20m 15. Gou 5.20ml Volume of diluted vinegar sample used in each titration (mL) #2 Initial buret reading (mL) Final buret reading (ml) Volume of NaOH Moles of NaOH Moles of...
I
need it right now, please help me??
PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The vinegar solution must be diluted by a factor of 5 to be suitable for titration. 1. Obtain - 20 ml of the stock vinegar solution from the fume hood. 2. Using the 10-ml. pipet, pipet" 10 mL of the stock solution to a 50-ml volumetric flask. 3. Fill the volumetric flask to the calibration line with distilled water. Be sure not to go over...
I dont know how to do this exercise please ignore my
answers
ME General Chemistry I Molarity of Acetic Acid in Vinegar: A Titration Experiment NaOH = 40.019/mols NaOH DATA AND CALCULATIONS STANDARDIZATION OF NaOH lesina Check the 2 (at least) trials O O O Check the 2 (at least) trials used to calculate the average molarity. Trial 1 Trial 2 Trial 3 Mass of KHP Moles of KHP 1991/ 37.50 m2 read - 1-0.72893 0 7599 0.75792- 16,59 Initial...
the
volume, moles and average need to be calculated from the calculated
numbers i got above
the
molarity of NaOH is 0.2998M
DATE SECTION - B. Analysis of Vinegar average molarity of NaOH (from part A), M HC,H,O, (aq) + NaOH(aq) → H,O (1) + NaC,H,O, (aq) Trial 1 Trial 2 Trial 3 volume of vinegar, ml 10mL 10mL 10mL volume of vinegar, L initial buret reading, mL final buret reading, ml 0.25mL 0.11mL 0.32mL 30.01ML 31.5mL 28.50mL volume of...
question 6
UUTUUDIY Report Titration Run 1 Run 3 Name Laura A cense Run 2 Volume of Vinegar Used o radac Concentration of NaOH 0.100 M 0.100 M 0.100 M 1.45 mL 1 1 19.68 ml 107.69 m2 Final Buret reading 19.68 m 36.78me lauo some Volume of NaOH Used 6.01sas 0.01710 0,ole 871 (Final Buret reading - 18.a I rolML 18h 16.87 Initial Buret reading) Calculations: 1. Calculate the number moles of base required to reach the endpoint for...
I need help calculating the mass percent and with the post lab
question #2.
Part 1 Mass Initial | Final Vol Nall Moles concen. KPHCG (ML) I (m2) Used (m2) KHP (mol)/NaOH(M) 0.28470.00 13.60r 13.600 10.00- 0.1025 2 UZ + ZANT 13.600 24.45 1 10.85 0.001128 10.40 Aug NaOH Concentration (M):0.1032 Part2 Vinegar identification # 4 Vinegar sample date: (011/ Vol Vinegat Initial Final Yol NaOH Mol Acotic Mass Acctic Mass % Titr ULST I OML Used (ml) Acid (mol)...
Need help filling out the rest of the table,
please.
1 M of NaOH
5% of acidity of acetic acid (vinegar)
n out Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar 419 Volume of Vinegar Density 1.005 g/ml Initial NaOH volume in syinge OmL Final NoOH volume in syringe 5.8m Volume of NaOH Delivered i mL 3. b ?? Moles of NaOH Delivered Moles of Acetic Acid...
analysis of vinegar lab question help
I'm trying to figure out how to find the molarity of acid
the average molarity from naOH concentration is 0.252M
Advertised % Acetic Acid B. Analysis of Vinegar (Acetie Acid) Trial #1 Trial #2 Trial #3 8. Volume of vinegar Final buret reading 1.00ml 1.00 mi 1.00ml 6.40 ml. 13.4 me 20.2 mi. 0.00 m. 6.40ml 64 ml. 6.40 mi 7.00 ml. 13,80 ml, M - M 10. Initial buret reading 11. Volume of...
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