Question

#3 please

1) Write the balanced chemical equation for the combustion of hexane, including physical states. Combustion reactions occur during burning, releasing heat and generally accompanied by light. Because of the heat, water will be produced as a vapor. 2 C 6 H 14 (g) + 19 O2(g) → 12 CO 2 (g) + 14 H2O(g) Use the balanced chemical equation above and stoichiometry to solve the following problems. 2) Calculate the maximum number of moles of carbon dioxide that can be produced from the combustion of 0.0590 moles of hexane. (12 mole CO2 =.354 mole .0 590 mole Cu Hill 2 mole Cutt 14 (g)) 3) What is the theoretical yield of carbon dioxide in kilograms that can be produced from the burning combustion) of 10.10 moles of hexane? Inveen gas are needed for the complete combustion of 5.700 moles of hexane?

Answer 1

2 C6H14(l) + 19 O2(g) ---> 12 CO2(g) + 14 H2O

The mole ratio of hexane : CO2 from above balanced equation is
2:12 [see the coefficients!] = 1:6   
So when 1 mole hexane used , 6 mole CO2 produced

when 10.10 mole hexane is present , 6*10.10 mole CO2 will be produced =60.60 mols

we have molar mass of CO2 = [12.01 + 2*16] g/mol = 44.01 g/mol

thus mass of CO2 present in 60.6 mols = 60.6 mols*44.01 g/mol = 2667 g = 2.667 Kg

Theoretical yield of CO2 = 2.667 kg
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