Question

I do not understand #5

1) Write the balanced chemical equation for the combustion of hexane, including physical states. Combustion reactions occur during burning, releasing heat and generally accompanied by light. Because of the heat, water will be produced as a vapor. 2 C6 H14 (g) + 19 02cg) 12 CO2 (g) + 14 H2O (9) Use the balanced chemical equation above and stoichiometry to solve the following problems. 2) Calculate the maximum number of moles of carbon dioxide that can be produced from the combustion of 0.0590 moles of hexane. 0 590 mole Cu Hiy ( 12 mole CO2 2 mole Cut 14 (9) 359 mole CO2 3) What is the theoretical yield of carbon dioxide in kilograms that can be produced from the burning combustion) of 10.10 moles of hexane? 4) How many moles of oxygen gas are needed for the complete combustion of 5.700 moles of hexane? 9 mole 02 5.700 mole Cu Hi4 = 54.15 mole O2 2 mole lol 5) How many liters of carbon dioxide will be released in the air per day if a plant burns 45.9 kg of hexane daily? Consider that one mole of carbon dioxide occupies 22.4 L of volume at normal temperatures. Hexane daily = 45.9kg

Answer 1

Answer: Balance combustion Reaction of Hexane 2C6H14 + 1902 12202 + 14 H2O * calculate the Number of mole of hexane mass af Hexane = 45.9kg 1kg = 1000 g . 45.9 kg = 45.9x1000 g 45900g molas mass cof Hexane = 86. 18 g/mol

Number of mole of Hexane - mars of Hexane molan mass of Hexane 4590 og 86.16 glmal - 532.60 mol Fromm the balance equcation 2 mol C6H4 Produced = 12 mol co2 .. 1 mol CollA would produced = 12 mol 602 - 6 mol coz 532.60 mol would produced = 6X532.60 mol cor, - 3195.63 mol cor at STP . 1 mol CO2 Contach = 22.4 L volume 3195.63 mol CO2 would contach - 22.4 x 3195.63 L volume - 71582.27 L volume of CO2 Answer "Please rate it"