Question

29) A student prepared a stock solution by dissolving 15.0 g of KOH in enough water to make 150 mL of solution. She then took 15.0 mL of the stock solution and diluted it with enough water to make water to make 65.0 mL of a final solution. What is the concentration of KOH for the final solution? A) O. 411 M B) 0.534 M C) 1.87 M D) 2.43 M 30) The mixing of which pair of reactants will result in a precipitation reaction? Mg(NO3)2(aq) + Na2CO3(aq) B) K2SO4(aq) + Cu(NO3)2(aq) C) NaClO4(aq) + (NH4)2S(aq) D) NH4Br(aq) + NH4l(aq) 31) What volume (in mL) will a sample of F2 gas occupy in a syringe at 5.5 atm, if the F2 has a volume of 25.0 mL at 1.2 atm? A) 11 mL B) 17 ml C) 3.8 ml D) 5.5 mL E) 7.6 mL 32) If a sample of 0.29 moles of Ar occupies 3.8 L under certain conditions, what volume will 0.66 moles occupy under the same conditions? A) 12 L B) 8.6 L C) 17 L D) 5.0 L E) 15 L
29,31,32 please

Answer 1

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29. molarity = man of kon xl (my melar mass VL) M: 15 gm *1 = 1.79 M 56 g/mole 0.15L. Now we take 15ml of it a dilute it with up to 65ml. - Mavi = M2V2 1.79 M X 15 ml = M2 X 65 mi . M2 = 1.75 MX 15ml 1 65ml correct option ® 31. Formula used P, V, = PzV₂ 5.5 odm x V, = 1.2atnx 25ml V = 1.2 atm x 25m) - 5.5 atm 1.75m x 15ml = 0.4119 Vi= 5.5mil 32. from PV = nRT as P,R,T are some so 3.82 0.29 mal V2 0.66 mole V2 = 3.8LX0.66mo! 0- 29 trial TV₂ = 8.6L) Scanned with CamScanner