Question

(1) Accelerator (acc): In the accelerator, there is only an uniform Electric field due to a potential difference Vacc across two vertical plates separated from a distance dacc. This E-field, Eacc, accelerates the charged particles. The charge emerges from the vertical plates with a speed v.

Skecth the situation describing the accelerator.

What are the EQUATIONS defining:

• the E-field between the plates, Eacc
• the acceleration acting on the charge, charge.acc
• the position as the charge travels, charge.pos
• the velocity as the charge travels, charge.v

(2) Velocity Selector (sel): In the velocity selector, there are two uniform fields: an Electric field, Esel, and a Magnetic field, Bsel, perpendicular to each other. Only the charges with a specific speed will be able to move undeflected between the two horizontal plates.

Sketch the situation describing the velocity selector.

What are the EQUATIONS defining:

• the E-field between the plates, Esel
• the electric force acting on the charge
• the magnetic force acting on the charge
• the total force acting on the charge, Fsel
• the acceleration on the charge, charge.acc
• the position as the charge travels, charge.pos
• the velocity as the charge travels, charge.v
• the momentum of the charge from velocity, charge.momentum

(3) Magnetic Chamber (cham): In the magnetic chamber, there is only an uniform magnetic field, Bcham. Once the undeflected charges reach the chamber, they will rotate in the field until they hit a detector.

Sketch the situation describing the magnetic chamber.

What are the EQUATIONS defining:

• the force acting on the charge, Fmag
• the momentum of the charge from the force, charge.momentum
• the velocity as the charge travels, charge.v
• the position as the charge travels, charge.pos

Answer 1

1) The electric field is giving by: The acceleration of the charge is giving by Newton's second law: a = Where: F = qe = Then: a = 9V dm The position as the charge travels: x = xo + vot+ at2 since the charge is starting from rest v = 0 and let bexo = 0 x = = at then: 1qV x = 2 dm The velocity is giving by: V = at = 9